Data and probability

Chapter 12 · 11 lessons · 276 questions

Unit 1: Probability and conditional probability

Key points

  • Probability = desired outcomes ÷\div total possible outcomes.
  • Write the fraction in words first, then put in the numbers.
  • ‘Given that’ and ‘of those who’ shrink the total to that group only.
  • A probability is always between 00 and 11.
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See it solved

Example

The table shows the results of a survey of 200200 students. A student in grade 1010 is chosen at random. What is the probability that the student is in a club?

Survey of 200 students
Two-way table of grade and club membership, with totals. Grade 9: 48 in a club, 52 not in a club, 100 in all. Grade 10: 36 in a club, 64 not in a club, 100 in all. Totals: 84 in a club, 116 not in a club, 200 students.
In a clubNot in a clubTotal
Grade 94852100
Grade 103664100
Total84116200

Worked by hand

The plan

  1. Determine the probability

Desmos: Desmos does not help you choose the right row or column. It can only turn your fraction into a decimal.

  1. Step 1: Determine the probability

    • In words: grade 1010 students in a club ÷\div all grade 1010 students.
    • ‘A student in grade 1010’ limits the total to the grade 1010 row: 100100 students.
    • Of those, 3636 are in a club.
    • 36100=925\dfrac{36}{100} = \dfrac{9}{25}, which is 0.360.36.
Answer: The correct answer is 925\dfrac{9}{25}, which is 0.360.36.

The same example in Desmos

  1. new graph

    Desmos shows: 0.360.36, at the right of the row. Click the fraction button beside it to see 925\dfrac{9}{25}.

Type
Desmos expression list: frac{36}{100}

Made with Desmos

Open Desmos (opens in a new tab)

Your turn

The table shows the results of a survey of 200200 students. A student who is in a club is chosen at random. What is the probability that the student is in grade 99?

Survey of 200 students
Two-way table of grade and club membership, with totals. Grade 9: 48 in a club, 52 not in a club, 100 in all. Grade 10: 36 in a club, 64 not in a club, 100 in all. Totals: 84 in a club, 116 not in a club, 200 students.
In a clubNot in a clubTotal
Grade 94852100
Grade 103664100
Total84116200
Show the answerHide the answer

Answer

The correct answer is 47\dfrac{4}{7}.

  1. Step 1: Determine the probability

    • In words: club members in grade 99 ÷\div all club members.
    • ‘A student who is in a club’ limits the total to the ‘In a club’ column: 8484 students.
    • Of those, 4848 are in grade 99.
    • 4884\dfrac{48}{84}. Divide the top and the bottom by 1212: 47\dfrac{4}{7}.

Traps

  • Using the grand total. 36200=0.18\dfrac{36}{200} = 0.18 is the probability that a student chosen from all 200200 is in grade 1010 and in a club. The question chooses only from grade 1010.
  • Swapping the condition. ‘A grade 99 student who is in a club’ and ‘a club member who is in grade 99’ have different totals: 48100\dfrac{48}{100} and 4884\dfrac{48}{84}.
Practice this lesson40 questions

Unit 2: Graphs of relationships

Key points

  • Each point on the graph pairs an input (how far across) with an output (how far up).
  • A piece that rises means the amount is going up. A flat piece means no change. A piece that falls means the amount is going down.
  • The steeper the piece, the faster the change.
  • Read the axis titles and their units before anything else.
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See it solved

Example

The graph shows Leo's distance from home, in miles, during a 6060-minute bike ride. For how many minutes was Leo not moving?

Time (minutes)Distance from home (miles)01020304050600246810

Worked by hand

The plan

  1. Determine what a flat piece means
  2. Read the flat piece

Desmos: Desmos cannot read a graph for you. It can only check the subtraction.

  1. Step 1: Determine what a flat piece means

    • The height of the graph is Leo's distance from home.
    • When Leo is not moving, his distance from home does not change, so the graph is flat.
  2. Step 2: Read the flat piece

    • The graph is flat from 2020 minutes to 3535 minutes.
    • 35−20=1535 - 20 = 15 minutes.
Answer: The correct answer is 1515.

The same example in Desmos

  1. new graph

    Desmos shows: 1515, as a check on the subtraction.

Type
Desmos expression list: 35-20

Made with Desmos

Open Desmos (opens in a new tab)

Your turn

The graph shows Leo's distance from home, in miles, during a 6060-minute bike ride. What was Leo's speed, in miles per minute, during the last 2525 minutes of the ride?

Time (minutes)Distance from home (miles)01020304050600246810
Show the answerHide the answer

Answer

The correct answer is 0.280.28.

  1. Step 1: Read the two ends of the piece

    • The last piece runs from (35,3)(35, 3) to (60,10)(60, 10).
  2. Step 2: Determine the slope

    • Distance: 10−3=710 - 3 = 7 miles.
    • Time: 60−35=2560 - 35 = 25 minutes.
    • 725=0.28\dfrac{7}{25} = 0.28 miles per minute.

Traps

  • Reading a flat piece as ‘riding straight ahead’. On this graph, flat means the distance from home is not changing: Leo has stopped.
  • Using the height instead of the change. At 6060 minutes the graph is at 1010 miles, but the last piece covers only 10−3=710 - 3 = 7 miles. 1025=0.4\dfrac{10}{25} = 0.4 is a wrong answer.
Practice this lesson12 questions

Unit 3: Scatterplots and lines of best fit

Key points

  • A scatterplot shows pairs of values as dots. The line of best fit shows the trend.
  • A predicted value is read from the line, not from a dot.
  • For the slope, use two grid points on the line, not two dots.
  • The slope is the predicted change in yy for each increase of 11 in xx.
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See it solved

Example

The scatterplot shows the ages and heights of 1010 trees, with a line of best fit. What height, in feet, does the line of best fit predict for a tree that is 88 years old?

Age (years)Height (feet)0123456789100481216202428

Worked by hand

The plan

  1. Read the line at the input

Desmos: Reading the line takes a few seconds. Desmos is a check: put two grid points of the line in a table and fit a line through them.

  1. Step 1: Read the line at the input

    • Find 88 on the horizontal axis.
    • Go straight up to the line of best fit, not to the dot.
    • The line is at 2020 there. The predicted height is 2020 feet.
    • The dot above 88 is at 1818 feet. That is one real tree, not the prediction.
Answer: The correct answer is 2020.

The same example in Desmos

  1. new graph, then Add item + and Table

    Table
    x1y1
    04
    1024

    Desmos shows: Two grid points on the line of best fit.

  2. Keys: y1~mx1+b

    Desmos shows: m=2m = 2 and b=4b = 4.

  3. Desmos shows: The line of best fit.

  4. Desmos shows: 2020, at the right of the row: the predicted height.

Type
Desmos expression list: a table of x1: 0, 10 and y1: 4, 24; y1~ mx1+b; f(x)=mx+b; f(8)
Look
Desmos graph of a table of x1: 0, 10 and y1: 4, 24; y1~ mx1+b; f(x)=mx+b; f(8), with (8, 20) labelled

Made with Desmos

Open Desmos (opens in a new tab)

Your turn

The scatterplot shows the ages and heights of 1010 trees, with a line of best fit. According to the line, by how many feet does the predicted height increase each year?

Age (years)Height (feet)0123456789100481216202428
Show the answerHide the answer

Answer

The correct answer is 22.

  1. Step 1: Determine the slope

    • Pick two grid points on the line: (0,4)(0, 4) and (10,24)(10, 24).
    • Rise: 24−4=2024 - 4 = 20 feet.
    • Run: 10−0=1010 - 0 = 10 years.
    • 2010=2\dfrac{20}{10} = 2 feet per year.

Traps

  • Reading the dot instead of the line. The dot above 88 years is at 1818 feet. That is one real tree. The prediction comes from the line: 2020 feet.
  • Taking the slope from two dots. The dots are scattered around the line. Use two points on the line itself, where it crosses grid lines.
Practice this lesson24 questions

Unit 4: Bar graphs, histograms and dot plots

Key points

  • In a bar graph, the height of a bar is the value for that category.
  • In a dot plot, each dot is one data value. Count the dots.
  • In a histogram, each bar counts the values in a range. You cannot see the exact values.
  • The number of data values is the total of the counts, not the number of bars.
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See it solved

Example

The bar graph shows the number of books that each of five students read in March. How many books did the five students read in all?

Books read in March
02468101214AnaBenCalDeeEliStudentNumber of books

Worked by hand

The plan

  1. Read the value of each bar
  2. Add the values

Desmos: Desmos cannot read a graph for you. After you have read the values, a list is only a check on the adding.

  1. Step 1: Read the value of each bar

    • Ana: 66. Ben: 99. Cal: 44. Dee: 1212. Eli: 77.
    • Ben's bar and Eli's bar end halfway between two numbered lines.
  2. Step 2: Add the values

    • 6+9=156 + 9 = 15.
    • 15+4=1915 + 4 = 19.
    • 19+12=3119 + 12 = 31.
    • 31+7=3831 + 7 = 38 books.
Answer: The correct answer is 3838.

The same example in Desmos

  1. new graph

    Desmos shows: The five values you read from the graph, as a list.

  2. Desmos shows: 3838, at the right of the row.

Type
Desmos expression list: L=[6,9,4,12,7]; operatorname{total}(L)

Made with Desmos

Open Desmos (opens in a new tab)

Your turn

The dot plot shows the number of pets owned by each student in a class. How many students own more than 22 pets?

Number of pets
01234
Show the answerHide the answer

Answer

The correct answer is 66.

  1. Step 1: Read the dots

    • ‘More than 22’ means 33 pets or 44 pets. It does not include 22.
    • There are 44 dots above 33 and 22 dots above 44.
  2. Step 2: Add the counts

    • 4+2=64 + 2 = 6 students.

Traps

  • Counting the bars instead of adding the values. There are 55 bars, but 55 is the number of students, not the number of books.
  • Including the boundary. ‘More than 22’ leaves out the students with exactly 22 pets. Adding their 55 dots gives 1111, a wrong answer.
Practice this lesson32 questions

Unit 5: The mean

Key points

  • The mean is the sum of the values divided by the number of values.
  • Turned round: sum = mean ×\times number of values. This is the key to most mean questions.
  • For a missing value, find the sum you need, then subtract the values you have.
  • For two groups together, add the two sums and divide by the total number of values.
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See it solved

Example

The mean of five test scores is 8282. Four of the scores are 7575, 8080, 8888 and 9090. What is the fifth score?

Worked by hand

The plan

  1. Set up the mean
  2. Determine the missing value

Desmos: Use sum = mean ×\times count by hand. Desmos is a check: put all the values in a list and ask for the mean.

  1. Step 1: Set up the mean

    • Sum = mean ×\times number of values.
    • 82⋅5=41082 \cdot 5 = 410. The five scores add up to 410410.
  2. Step 2: Determine the missing value

    • Add the four known scores: 75+80=15575 + 80 = 155.
    • 155+88=243155 + 88 = 243.
    • 243+90=333243 + 90 = 333.
    • The fifth score is 410−333=77410 - 333 = 77.
    • Check: 333+775\dfrac{333 + 77}{5} =4105= \dfrac{410}{5} =82= 82. It matches.
Answer: The correct answer is 7777.

The same example in Desmos

  1. new graph

    Desmos shows: All five scores, with your answer as the fifth.

  2. Desmos shows: 8282, at the right of the row. The mean matches, so 7777 is right.

Type
Desmos expression list: L=[75,80,88,90,77]; operatorname{mean}(L)

Made with Desmos

Open Desmos (opens in a new tab)

Your turn

A class of 2020 students has a mean score of 7070 on a test. A second class of 3030 students has a mean score of 8080 on the same test. What is the mean score of all 5050 students?

Show the answerHide the answer

Answer

The correct answer is 7676.

  1. Step 1: Determine each sum

    • First class: 70⋅20=1,40070 \cdot 20 = 1{,}400.
    • Second class: 80⋅30=2,40080 \cdot 30 = 2{,}400.
  2. Step 2: Set up the mean

    • All the scores add up to 1,400+2,4001{,}400 + 2{,}400 =3,800= 3{,}800.
    • There are 20+30=5020 + 30 = 50 students.
    • 3,80050=76\dfrac{3{,}800}{50} = 76.

Traps

  • Averaging the four known scores. 3334=83.25\dfrac{333}{4} = 83.25 is the mean of four scores. It is not the missing fifth score.
  • Averaging two means without the group sizes. 70+802=75\dfrac{70 + 80}{2} = 75 treats the classes as the same size. The bigger class pulls the mean toward 8080: the answer is 7676.
Practice this lesson28 questions

Unit 6: The median

Key points

  • The median is the middle value when the values are in order.
  • With an odd number of values, it is the one in the middle.
  • With an even number of values, it is the mean of the two middle values.
  • In a frequency table, find the middle position by adding up the counts.
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See it solved

Example

The numbers of points a team scored in 88 games are 1212, 77, 1515, 99, 2020, 77, 1111 and 1414. What is the median number of points?

Worked by hand

The plan

  1. Sort the numbers
  2. Determine the middle number

Desmos: With a list of values, Desmos is quicker: type the list as given and ask for the median. Desmos sorts it for you.

  1. Step 1: Sort the numbers

    • From least to greatest: 77, 77, 99, 1111, 1212, 1414, 1515, 2020.
  2. Step 2: Determine the middle number

    • There are 88 values, an even number. The middle two are the 44th and the 55th.
    • They are 1111 and 1212.
    • 11+122\dfrac{11 + 12}{2} =232= \dfrac{23}{2} =11.5= 11.5.
Answer: The correct answer is 11.511.5.

The same example in Desmos

  1. new graph

    Desmos shows: The eight values, in the order given.

  2. Desmos shows: 11.511.5, at the right of the row.

Type
Desmos expression list: L=[12,7,15,9,20,7,11,14]; operatorname{median}(L)

Made with Desmos

Open Desmos (opens in a new tab)

Your turn

The table shows the number of siblings of each of 2525 students. What is the median number of siblings?

Siblings of 25 students
Frequency table. Number of siblings 0: 4 students. 1: 9 students. 2: 7 students. 3: 3 students. 4: 2 students.
Number of siblingsNumber of students
04
19
27
33
42
Show the answerHide the answer

Answer

The correct answer is 11.

  1. Step 1: Determine the middle position

    • There are 2525 values. The middle one is the 1313th, because 1212 values are below it and 1212 are above it.
  2. Step 2: Count up to the middle position

    • 00 siblings: students 11 to 44.
    • 11 sibling: the next 99 students, numbers 55 to 1313.
    • The 1313th student has 11 sibling. The median is 11.

Traps

  • Not sorting first. In the order given, the middle two values are 99 and 2020, which gives 14.514.5, a wrong answer.
  • Taking the middle row of a frequency table. The middle row is 22 siblings, but the rows hold different numbers of students. Count positions instead: the median is 11.
Practice this lesson24 questions

Unit 7: Box plots and quartiles

Key points

  • A box plot shows five numbers: the minimum, the first quartile Q1Q_1, the median, the third quartile Q3Q_3 and the maximum.
  • The box runs from Q1Q_1 to Q3Q_3. It holds the middle half of the data.
  • Range = maximum −- minimum. Interquartile range =Q3−Q1= Q_3 - Q_1.
  • A box plot does not show the mean or the number of values.
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See it solved

Example

The box plot summarizes the heights, in inches, of the plants in a garden. What is the interquartile range of the heights?

Plant heights (inches)
8121620242832

Worked by hand

The plan

  1. Read the five numbers
  2. Determine the interquartile range

Desmos: Desmos cannot read a box plot for you. Read the five numbers yourself. Desmos can only check the subtraction.

  1. Step 1: Read the five numbers

    • Minimum: 1010. Q1Q_1: 1414. Median: 1717. Q3Q_3: 2222. Maximum: 3030.
    • Q1Q_1 and Q3Q_3 are the two ends of the box.
  2. Step 2: Determine the interquartile range

    • Q3−Q1Q_3 - Q_1 =22−14= 22 - 14 =8= 8 inches.
Answer: The correct answer is 88.

The same example in Desmos

  1. new graph

    Desmos shows: 88: the interquartile range, as a check on the subtraction.

  2. Desmos shows: 2020: the range. It is a different measure, from the ends of the whiskers.

Type
Desmos expression list: 22-14; 30-10

Made with Desmos

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Your turn

The box plots summarize the test scores of two classes. By how many points does the range of the scores in class A exceed the range of the scores in class B?

Test scores
4550556065707580859095100Class AClass B
Show the answerHide the answer

Answer

The correct answer is 1515.

  1. Step 1: Read the minimum and maximum of each class

    • Class A: minimum 5050, maximum 9595.
    • Class B: minimum 5555, maximum 8585.
  2. Step 2: Determine each range

    • Class A: 95−50=4595 - 50 = 45.
    • Class B: 85−55=3085 - 55 = 30.
    • 45−30=1545 - 30 = 15 points.

Traps

  • Using the whiskers for the interquartile range. 30−10=2030 - 10 = 20 is the range, from the minimum to the maximum. The interquartile range uses the ends of the box: 22−14=822 - 14 = 8.
  • Reading the line in the box as the mean. That line is the median, 1717. A box plot never shows the mean.
Practice this lesson12 questions

Unit 8: Standard deviation and range

Key points

  • Range = greatest value −- least value.
  • Standard deviation measures how spread out the values are around the mean.
  • Values bunched close to the mean give a small standard deviation. Values far from the mean give a large one.
  • You never calculate a standard deviation on the test. You compare two data sets by eye.
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See it solved

Example

Data set A is 4848, 4949, 5050, 5151, 5252. Data set B is 3030, 4040, 5050, 6060, 7070. Which statement about the two data sets is true?

  1. AThe means are equal, and set A has the greater standard deviation.
  2. BThe means are equal, and set B has the greater standard deviation.
  3. CSet A has the greater mean and the greater standard deviation.
  4. DSet B has the greater mean, and the standard deviations are equal.

Worked by hand

The plan

  1. Compare the means
  2. Compare the spreads

Desmos: You are not asked to calculate a standard deviation, and comparing by eye is quicker. Desmos can confirm which one is larger, as a check.

  1. Step 1: Compare the means

    • Set A: 48+49+5048 + 49 + 50 =147= 147, and 147+51+52147 + 51 + 52 =250= 250.
    • The mean of set A is 2505=50\dfrac{250}{5} = 50.
    • Set B: 30+40+5030 + 40 + 50 =120= 120, and 120+60+70120 + 60 + 70 =250= 250.
    • The mean of set B is 2505=50\dfrac{250}{5} = 50.
    • The means are equal. That rules out choices C and D.
  2. Step 2: Compare the spreads

    • In set A, every value is within 22 of the mean.
    • In set B, the values are up to 2020 away from the mean.
    • Set B is more spread out, so it has the greater standard deviation: choice B.
Answer: The correct answer choice is B: both means are 5050, and set B is more spread out.

The same example in Desmos

  1. new graph

    and

    Desmos shows: The two data sets as lists.

  2. and

    Desmos shows: 5050 and 5050: the means are equal.

  3. and

    Desmos shows: About 1.581.58 and 15.8115.81: set B has the greater standard deviation.

Type
Desmos expression list: A=[48,49,50,51,52]; B=[30,40,50,60,70]; operatorname{mean}(A); operatorname{mean}(B); operatorname{stdev}(A); operatorname{stdev}(B)

Made with Desmos

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Your turn

The daily high temperatures in a town for one week were 6161, 5858, 7070, 6666, 5959, 7373 and 6464 degrees. What is the range of these temperatures, in degrees?

Show the answerHide the answer

Answer

The correct answer is 1515.

  1. Step 1: Determine the greatest and least values

    • The greatest value is 7373. The least value is 5858.
  2. Step 2: Determine the range

    • 73−58=1573 - 58 = 15 degrees.

Traps

  • Thinking that bigger numbers mean a bigger standard deviation. Spread is about distance from the mean, not size. The set 1,0011{,}001, 1,0021{,}002, 1,0031{,}003 has a small standard deviation.
  • Subtracting the first and last values as listed. 64−61=364 - 61 = 3 uses the order in the list. The range uses the greatest and the least: 73−58=1573 - 58 = 15.
Practice this lesson40 questions

Unit 9: What changes when the data change

Key points

  • Adding the same number to every value moves the mean and the median by that number. The range and the standard deviation stay the same.
  • Multiplying every value by a number multiplies the mean, the median, the range and the standard deviation by it.
  • One very large or very small new value pulls the mean toward it. The median barely moves.
  • Check each measure one at a time.
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See it solved

Example

The five workers at a small company earn 4040, 4242, 4545, 4848 and 5050 thousand dollars a year. A manager who earns 150150 thousand dollars a year joins the company. Which statement is true about the six salaries, compared with the first five?

  1. AThe mean and the median increase by the same amount.
  2. BThe mean increases by more than the median.
  3. CThe median increases by more than the mean.
  4. DNeither the mean nor the median changes.

Worked by hand

The plan

  1. Evaluate each measure before the change
  2. Evaluate each measure after the change
  3. Compare the changes

Desmos: Reasoning is quicker: one very large value pulls the mean, not the median. Desmos is a check: put both lists in and compare.

  1. Step 1: Evaluate each measure before the change

    • Sum: 40+42+4540 + 42 + 45 =127= 127, and 127+48+50127 + 48 + 50 =225= 225.
    • Mean: 2255=45\dfrac{225}{5} = 45.
    • Median: the middle of five sorted values is the 33rd, which is 4545.
  2. Step 2: Evaluate each measure after the change

    • Sum: 225+150=375225 + 150 = 375. Mean: 3756=62.5\dfrac{375}{6} = 62.5.
    • Median: with six values, take the mean of the 33rd and the 44th. 45+482=46.5\dfrac{45 + 48}{2} = 46.5.
  3. Step 3: Compare the changes

    • Mean: 62.5−45=17.562.5 - 45 = 17.5 more.
    • Median: 46.5−45=1.546.5 - 45 = 1.5 more.
    • The mean increases by more than the median: choice B.
Answer: The correct answer choice is B: the mean rises by 17.517.5 and the median by only 1.51.5 (in thousands of dollars).

The same example in Desmos

  1. new graph

    Desmos shows: The first five salaries.

  2. and

    Desmos shows: 4545 and 4545.

  3. Desmos shows: The six salaries.

  4. and

    Desmos shows: 62.562.5 and 46.546.5. The mean moved by 17.517.5, the median by 1.51.5.

Type
Desmos expression list: L=[40,42,45,48,50]; operatorname{mean}(L); operatorname{median}(L); M=[40,42,45,48,50,150]; operatorname{mean}(M); operatorname{median}(M)

Made with Desmos

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Your turn

The mean of 3030 quiz scores is 6868, and the range of the scores is 4040. Then 55 points are added to every score. What is the range of the new scores?

Show the answerHide the answer

Answer

The correct answer is 4040.

  1. Step 1: Evaluate each measure

    • Adding 55 to every score moves the greatest score up by 55 and the least score up by 55.
    • The gap between them does not change, so the range is still 4040.
    • The mean does change: it becomes 68+5=7368 + 5 = 73.

Traps

  • Assuming every measure changes together. One new value moved the mean by 17.517.5 but the median by only 1.51.5. Work out each measure by itself.
  • Adding the 55 to the range. Both ends move up by 55, so the gap stays 4040. 4545 is a wrong answer.
Practice this lesson12 questions

Unit 10: From a sample to the population: estimates and margin of error

Key points

  • A random sample stands in for the whole population.
  • Estimate = sample proportion ×\times population size.
  • The margin of error gives a range: from the estimate minus the margin to the estimate plus the margin. The true value is likely to be inside it.
  • A larger random sample gives a smaller margin of error.

See it solved

Example

A town has 6,0006{,}000 households. In a random sample of 150150 of them, 4545 households have a dog. Based on the sample, what is the best estimate of the number of households in the town that have a dog?

Worked by hand

The plan

  1. Determine the sample proportion
  2. Determine the estimate

Desmos: The reasoning is done by hand. Desmos only keeps the calculation on one row, as a check.

  1. Step 1: Determine the sample proportion

    • 4545 of the 150150 households in the sample have a dog.
    • 45150=0.30\dfrac{45}{150} = 0.30.
  2. Step 2: Determine the estimate

    • Apply the same proportion to the whole town.
    • 0.30⋅6,0000.30 \cdot 6{,}000 =1,800= 1{,}800 households.
Answer: The correct answer is 1,8001{,}800.

The same example in Desmos

  1. new graph

    Keys: 45/150 → *6000

    Desmos shows: 18001800, at the right of the row.

Type
Desmos expression list: frac{45}{150}·6000

Made with Desmos

Open Desmos (opens in a new tab)

Your turn

A poll of a random sample of voters estimates that 62%62\% of all voters support a plan, with a margin of error of 4%4\%. Based on the poll, what is the least plausible percent of all voters who support the plan?

Show the answerHide the answer

Answer

The correct answer is 58%58\%.

  1. Step 1: Determine the plausible range

    • Estimate minus margin: 62−4=5862 - 4 = 58.
    • Estimate plus margin: 62+4=6662 + 4 = 66.
    • The plausible range is from 58%58\% to 66%66\%. The least is 58%58\%.

Traps

  • Treating the estimate as exact. 1,8001{,}800 is the best estimate, not a certain count. A different random sample would give a slightly different number.
  • Using the margin on one side only. The range is 44 either side of 6262, so it runs from 58%58\% to 66%66\%. ‘From 62%62\% to 66%66\%’ is a wrong answer.
Practice this lesson28 questions

Unit 11: What a study can conclude

Key points

  • Ask two questions about any study.
  • Was the sample chosen at random from a population? Then the results apply to that population, and only to it.
  • Were the treatments assigned at random? Then the study can show that the treatment caused the result.
  • Without random assignment, a link between two things is only an association, not a cause.
  • Be wary of the words ‘all’, ‘always’ and ‘proves’.

See it solved

Example

A researcher chose 100100 students at random from the students at one high school. She assigned 5050 of them at random to use a study app for a month. The other 5050 did not use it. On a test at the end of the month, the app group had a mean score of 8484 and the other group had a mean score of 7676. Which conclusion is best supported?

  1. AThe app causes higher test scores for all high school students.
  2. BThe app caused higher test scores for students at this high school.
  3. CUsing the app is linked to higher scores at this high school, but the study cannot show cause.
  4. DNo conclusion is possible, because only 100100 students took part.

Worked by hand

The plan

  1. Check how the sample was chosen
  2. Check how the treatment was assigned
  3. Check the size of the effect

Desmos: Desmos does not help here: the question is about how the study was run, not about a calculation. It can only check the subtraction.

  1. Step 1: Check how the sample was chosen

    • The 100100 students were chosen at random from one high school.
    • So the results apply to the students at that school, and only to them.
    • That rules out choice A, which talks about all high school students.
  2. Step 2: Check how the treatment was assigned

    • The students were assigned to the app at random.
    • Random assignment lets a study show cause. That rules out choice C.
  3. Step 3: Check the size of the effect

    • 84−76=884 - 76 = 8 points.
    • A random sample of 100100 students is large enough to support a conclusion. That rules out choice D.
Answer: The correct answer choice is B: the app raised the mean score by about 88 points, for students at this high school.

The same example in Desmos

  1. new graph

    Desmos shows: 88: the difference between the two mean scores, as a check on the subtraction.

Type
Desmos expression list: 84-76

Made with Desmos

Open Desmos (opens in a new tab)

Your turn

A survey of a random sample of 500500 adults in a city asked about walking and sleep. Of the 200200 adults who walk every day, 140140 said they sleep well. Of the 300300 who do not, 150150 said they sleep well. Which conclusion is best supported?

  1. AWalking every day causes better sleep for adults in the city.
  2. BWalking every day causes better sleep for all adults.
  3. CAdults in the city who walk every day are more likely to say they sleep well, but the survey does not show cause.
  4. DNo conclusion is possible, because the adults chose for themselves whether to walk.
Show the answerHide the answer

Answer

The correct answer choice is C: 70%70\% of the walkers and 50%50\% of the others sleep well. That is a link, not a cause.

  1. Step 1: Check how the sample was chosen

    • The adults were chosen at random from one city.
    • So the results apply to adults in that city. That rules out choice B.
  2. Step 2: Check how the treatment was assigned

    • Nobody assigned the walking. The adults chose for themselves.
    • Without random assignment, the survey cannot show cause. That rules out choice A.
  3. Step 3: Check the size of the effect

    • Walkers: 140200=0.70\dfrac{140}{200} = 0.70, which is 70%70\%.
    • The others: 150300=0.50\dfrac{150}{300} = 0.50, which is 50%50\%.
    • The walkers are more likely to say they sleep well. That link is a real finding, so choice D is wrong too.

Traps

  • Stretching the population. A sample from one school says nothing certain about other schools. ‘All high school students’ is choice A, a wrong answer.
  • Claiming cause without random assignment. In Your turn, the adults chose for themselves whether to walk. Something else, such as their health or their free time, could explain both the walking and the sleep.
Practice this lesson24 questions
Typing tips for Desmos
  • In the keys lines, → means the right-arrow key.
  • Typing / starts a fraction, and everything after it goes into the denominator until you press →. So 42/120*100 typed straight through becomes 42 ÷ (120 × 100). Type 42/120 → *100 instead.
  • Type y1 and Desmos shows y₁: a digit typed straight after a letter becomes a subscript. If you type the underscore yourself (y_1), press → after the digit: a ~ typed next lands inside the subscript (+, − and = leave it by themselves).
  • The ~ key is Shift + ` on most keyboards (the key left of 1). Use ~, not =: ~ asks Desmos to find the unknown letters; = only draws or defines.
  • A letter that already has a value, such as a slider m = 1 left over from earlier, is held fixed by a ~ fit, with no warning. Start a new graph, or delete old sliders, before each question.
  • Typing ^ or sqrt works the same way: press → to come back down from an exponent or out of a square root before typing the rest.

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